Result
Preliminary calculation: This tool is for quick sizing and information. In real projects, load calculation, selection and commissioning require engineering calculations and a site survey. Results are approximate values.
Formulas
P_electric [kW] = Q_cooling [kW] / COPCOP = EER [BTU/Wh] / 3.412Annual cost = P_electric × hours × unit priceNominal COP/EER is the efficiency under laboratory conditions. For inverter units running at part load, seasonal efficiency (SEER, SCOP) is usually more meaningful. When selecting a unit, the initial investment and the annual operating cost should be evaluated together.
- Regular maintenance preserves efficiency; dirty filters and coils increase consumption
- Low refrigerant reduces capacity and increases consumption
- Annual operating hours vary widely with the space and climate
Frequently asked questions
What is the difference between COP and EER?
COP is the ratio of output kW to input kW; EER is the same ratio in BTU/Wh. COP = EER / 3.412.
How do you find the annual hours?
It is the total annual time as if the unit ran at full load. For an estimate, the occupancy hours of the space and the climate conditions are taken into account.
Does an inverter air conditioner really save energy?
In spaces with long part-load operating hours, it generally uses less energy than fixed-speed units; the gain depends on usage.